1/

MnO₂+ 4HCl\(\rightarrow\) MnCl₂+ Cl₂+ 2H₂O

Cl₂+H₂\(\xrightarrow[]{as}\) 2HCl

HCl+ NaOH\(\rightarrow\) NaCl+ H₂O

2NaCl\(\xrightarrow[]{đpnc}\) 2Na+ Cl₂

Cl₂+ SO₂+ 2H₂O\(\rightarrow\) H₂SO₄+ 2HCl

H₂SO_{4 đặc}+ NaCl_{tinh thể}\(\xrightarrow[]{< 250\cdot C}\) NaHSO₄+ HCl

4/

H₂SO_{4 đặc}+ NaCl_{tinh thể}\(\xrightarrow[]{< 250\cdot C}\) NaHSO₄+ HCl

MnO₂+ 4HCl\(\rightarrow\) MnCl₂+ Cl₂+ 2H₂O

3Cl₂+ 6KOH_đặc\(\rightarrow\) KClO₃+ 5KCl+ 3H₂O

2KClO₃\(\xrightarrow[MnO2]{to}\) 2KCl+ 3O₂

2KCl\(\xrightarrow[]{đpnc}\) K+ Cl₂

Cl₂+ Ca(OH)₂\(\xrightarrow[]{30\cdot C}\) CaOCl₂+ H₂O

1, \(MnO_2+4HCl\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)

\(Cl_2+H_2\underrightarrow{as,t^o}2HCl\)

\(HCl+NaOH\rightarrow NaCl+H_2O\)

\(2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2+H_2\)

\(4Cl_2+4H_2O+H_2S\rightarrow H_2SO_4+8HCl\)

\(H_2SO_4+NaCl\underrightarrow{>400^oC}Na_2SO_4+HCl\uparrow\)

2, \(2KMnO_4+18HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)

\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)

\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3\downarrow+3KCl\)

\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)

3, \(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)

\(3Cl_2+2Fe\underrightarrow{t^o}2FeCl_3\)\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\downarrow\)

\(2NaCl+H_2SO_4\underrightarrow{>400^oC}Na_2SO_4+2HCl\)

\(2HCl+Cu\left(OH\right)_2\rightarrow CuCl_2+2H_2O\)

\(CuCl_2+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2AgCl\downarrow\)

4, \(H_2SO_4+2NaCl\underrightarrow{>400^oC}Na_2SO_4+2HCl\uparrow\)

\(4HCl+MnO_2\underrightarrow{t^o}MnCl_2+Cl_2+2H_2O\)

\(3Cl_2+6KOH\underrightarrow{80-100^oC}5KCl+KClO_3+3H_2O\)

\(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)

\(2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2+H_2\)

\(Cl_2+Ca\left(OH\right)_2\underrightarrow{30^oC}CaOCl_2+H_2O\)

Bạn tham khảo nhé!

1.

\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+H_2O\)

\(Cl_2+H_2\underrightarrow{^{to}}2HCl\)

\(NaOH+HCl\rightarrow NaCl+H_2O\)

\(2NaCl\underrightarrow{^{đpnc}}2Na+Cl_2\)

\(Cl_2+SO_2+2H_2O\rightarrow2HCl+H_2SO_4\)

\(NaCl+H_2SO_{4_đ}\underrightarrow{^{to}}NaHSO_4+HCl\)

2.

\(2KMnO_4+16HCl\rightarrow2KCl+2MnCl_2+5Cl_2+8H_2O\)

\(2Fe+3Cl_2\underrightarrow{^{to}}2FeCl_3\)

\(FeCl_3+3KOH\rightarrow Fe\left(OH\right)_3+3KCl\)

\(2KCl+2H_2O\underrightarrow{^{đpmn}}2KOH+H_2+Cl_2\)

3.

\(MnO_2+4HCl\underrightarrow{^{to}}MnCl_2+Cl_2+2H_2O\)

\(2Fe+3Cl_2\underrightarrow{^{to}}2FeCl_3\)

\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)

\(NaCl+H_2SO_{4_Đ}\underrightarrow{^{to}}NaHSO_4+HCl\)

\(CuO+2HCl\rightarrow CuCl_2+H_2O\)

\(CuCl_2+2AgNO_3\rightarrow2AgCl+Cu\left(NO_3\right)_2\)

4.

\(NaCl+H_2SO_{4_Đ}\underrightarrow{^{to}}NaHSO_4+HCl\)

\(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)

\(3Cl_2+6KOH\underrightarrow{^{to}}5KCl+KClO_3+3H_2O\)

\(KClO_3+6HCl\rightarrow KCl+3Cl_2+3H_2O\)

\(Cl_2+CaO\underrightarrow{^{to}}CaOCl_2\)

\(1) 2Fe(OH)_3 \xrightarrow{t^o} Fe_2O_3 + 3H_2O\\ 2) Na_2O + H_2SO_4 \to Na_2SO_4 + H_2O\\ 3) ZnO + H_2SO_4 \to ZnSO_4 + H_2O\\ 4) NaOH + HCl \to NaCl + H_2O\\ 5) 2NaOH + CO_2 \to Na_2CO_3 + H_2O\\ 6) Mg + 2HCl \to MgCl_2 + H)2\\ 7) Cu + 2AgNO_3 \to Cu(NO_3)_2 + 2Ag\\ 8) 2K + S \xrightarrow{t^o} K_2S\)

1, $2Fe(OH)_3\xrightarrow{t^o} Fe_2O_3+3H_2O$

2, $H_2SO_4+2NaOH\to Na_2SO_4+2H_2O$

3, $H_2SO_4+Zn(OH)_2\to ZnSO_4+2H_2O$

4, $NaOH+HCl\to NaCl+H_2O$

5, $2NaOH+CO_2\to Na_2CO_3+H_2O$

6, $Mg+2HCl\to MgCl_2+H_2$

7, $Cu+2AgNO_3\to Cu(NO_3)_2+2Ag$

8, $2K+S\xrightarrow{t^o} K_2S$

câu 1:

\(Fe^{+2}So_4+H_2SO_4+KMn^{+7}O_4\rightarrow Fe^{+3}_2\left(SO_4\right)_3+Mn^{+2}SO_4+K_2SO_4+H_2O\left(1\right)\)

\(Fe^{+2}So_4+H_2SO_4+K_2Cr^{+6}_2O_7\rightarrow Fe^{+3}_2\left(SO_4\right)_3+Cr^{+3}_2\left(SO_4\right)_3+K_2SO_4+H_2O\left(2\right)\)

Áp dụng bảo toàn e cho 2 phương trình trên:

phương trình (1) <=> \(n_{Fe}\times1=n_{Mn}\times5\) (mỗi Fe nhường 1e, mỗi Mn nhận 5e, số e nhường bằng số e nhận)

phương trình (2) <=> \(n_{Fe}\times1=n_{Cr_2}\times6\)(mỗi Fe nhường 1e, mỗi Cr nhận 3e =>mỗi Cr2 nhận 6e)

=>\(n_{Mn}\times5=n_{Cr_2}\times6\Leftrightarrow n_{k_2Cr_2O_7}=n_{Cr_2}=\dfrac{5}{6}n_{Mn}=\dfrac{5}{6}n_{KMnO_4}=\dfrac{5}{6}\times0,06\times0,02=0,001\)

=> \(v=\dfrac{0,001}{0,02}=0,05\left(l\right)\)

câu 2:

sơ đồ phản ứng: \(Mg^0,Al^0+Cl^0_2,O^0_2\rightarrow Mg^{+2}Cl_2^{-1},Mg^{+2}O^{-2},Al^{+3}Cl_3^{-1},Al_2^{+3}O_3^{-2}\)

\(n_{Mg}=\dfrac{4,8}{24}=0,2;n_{Al}=\dfrac{8,1}{27}=0,3\)

Bảo toàn electron:\(n_{Mg}\cdot2+n_{Al}\cdot3=n_{Cl}\cdot1+n_O\cdot2=1,3\)

\(n_{Cl}\cdot35,5+n_O\cdot16=37,05-4,8-8,1=24,15\)(bảo toàn khối lượng)

giải hệ trên =>\(n_{Cl}=0,5;n_O=0,4\)

=>\(n_{Cl_2}=\dfrac{1}{2}n_{Cl}=0,5\cdot\dfrac{1}{2}=0,25;n_{O_2}=\dfrac{1}{2}n_O=\dfrac{1}{2}\cdot0,4=0,2\)

\(\Rightarrow v\%Cl_2=\dfrac{0,25}{0,25+0,2}\cdot100\%=55,56\%\)

\(v\%Cl_2=\dfrac{0,2}{0,25+0,2}\cdot100\%=44,44\%\)

C. 1 và 3 

$1) 3Fe + 2O_2 \xrightarrow{t^o} Fe_3O_4$

$2) 4P + 5O_2 \xrightarrow{t^o} 2P_2O_5$
$3) 2Na + S \xrightarrow{t^o} Na_2S$
$4) 2KClO_3 \xrightarrow{t^o} 2KCl +3 O_2$
$5) 2KMnO_4 \xrightarrow{t^o} K_2MnO_4 + MnO_2 + O_2$
$6) CuO + H_2 \xrightarrow{t^o} Cu + H_2O$
$7) 2H_2 + O_2 \xrightarrow{t^o} 2H_2O$

1,2,3,7 : Phản ứng hóa hợp

4,5 : Phản ứng phân hủy

6 : Phản ứng thế

1. 3Fe + 2O₂ ---> Fe₃O₄

2. 4P + 5O₂ ---> 2P₂O₅

4. 2KClO₃ ---> 2KCl + 3O₂

5. 2KMnO₄ ---> K₂MnO₄ + MnO₂ + O₂

6. H₂ + CuO ---> Cu + H₂O

7. 4H₂ + O₂ ---> 2H₂O